 ans  =
 
    1.  
 
-->//Chapter 17
-->//Example 17_10
-->//Page 412
-->clear;clc;
-->q=50000;
-->x=20;
-->b=10;
-->n1=3;
-->n2=9;
-->//from the derivation
-->sckva1=(q/x+q*(n1-1)/(b*n1+x))*100;
-->sckva2=(q/x+q*(n2-1)/(b*n2+x))*100;
-->//When n is very large
-->sckva3=(q/x+q/b)*100;
-->printf("(i) Short circuit kVA with %d sections = %d kVA \n\n", n1, sckva1);
(i) Short circuit kVA with 3 sections = 450000 kVA 

-->printf("(ii) Short circuit kVA with %d sections = %d kVA \n\n", n2, sckva2);
(ii) Short circuit kVA with 9 sections = 613636 kVA 

-->printf("(iii) Short circuit kVA when n is very large = %d kVA \n\n", sckva3);
(iii) Short circuit kVA when n is very large = 750000 kVA 

-->diary(0)
