 
 example 5.15   

tan phi=  0.750000
 
 FOR ALTERNATOR A   

tan phi_a=  0.484322
 
 reactive load=active load*tan phi   
 
 Active load=8000kW   
reactive load=  3874 KVAr
 
 Active Load A=5000kW\n   
Reactive load A=  2421kVAr
Active load of B=  3000kW
Reactive load of B=  3578kVAr
phi_b=  50.024676
Power Factor of B=  0.642458 