--> //initializations

--> H1=2.4 //m (open well depression)
 H1  = 

   2.4


--> h=1.5 //m (recuperated by an amount)
 h  = 

   1.5


--> D=3 //m (diameter of well)
 D  = 

   3.


--> H=3 //m (depression head)
 H  = 

   3.


--> t=60 //min (time)
 t  = 

   60.


--> //calculations

--> T=t/60 //(time)
 T  = 

   1.


--> H2=H1-h //(reduction in height)
 H2  = 

   0.9


--> d=(1/T)*log(H1/H2) //(K/A) (specific yield)
 d  = 

   0.9808293


--> A=(%pi*(D^2))/4 //(area)
 A  = 

   7.0685835


--> q=d*A*H //(discharge)
 q  = 

   20.79922


--> //results

--> printf('discharge=%f',q) //m^3/hr
discharge=20.799220
